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ergodicity
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@@ -245,6 +245,10 @@ Nassim Taleb in \textit{Fooled By Randomness} describes this event with an analo
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1/10,000 chance of harm? In this case, many less-than-rational actors use the game repeatedly to acquire wealth indefinitely, forgetting or even outright ignorant
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1/10,000 chance of harm? In this case, many less-than-rational actors use the game repeatedly to acquire wealth indefinitely, forgetting or even outright ignorant
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that eventually the unlikely, or, as the actor would see it, the unthinkable, happens and all of the gains are completely negated.
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that eventually the unlikely, or, as the actor would see it, the unthinkable, happens and all of the gains are completely negated.
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Averaging a game of Russian Roulette leaves the average person \$833,333 richer, but this is where ergodicity comes into play. There is no 'average' person,
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you can play and win many times but when you eventually bust you lose everything you put in. Removing the vocabulary from this concept, averaging many first
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iterations will not necessarily predict the performance of an experiment with many iterations.
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\subsubsection{Fooled By Randomness}
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\subsubsection{Fooled By Randomness}
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While most statisticians are familiar with techniques to remove noise to get a clearer picture of long-term trends, many forget that noise over longer terms can
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While most statisticians are familiar with techniques to remove noise to get a clearer picture of long-term trends, many forget that noise over longer terms can
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materialize as highly improbable events. For instance, it is improbable to flip a fair coin and have heads land face up 5 times in a row, but if the coin is flipped
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materialize as highly improbable events. For instance, it is improbable to flip a fair coin and have heads land face up 5 times in a row, but if the coin is flipped
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@@ -734,7 +738,7 @@ calculated:
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Two consecutive sunny days:
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Two consecutive sunny days:
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\[(\frac{5}{6} * .95) * (.9 * .95) \approx 0.677 \]
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\[(\frac{5}{6} * .95) * (.9 * .95) \approx 0.677 \]
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Cloudy, Sunny:
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Cloudy, Sunny:
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\[(\frac{1}{6} * .6) * (.1 * .95) = 0.0095 \]
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\[(\frac{1}{6} * .6) * (.5 * .95) = 0.048 \]
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\end{center}
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\end{center}
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Hence, we can eliminate the \([\text{Cloudy, Sunny}]\) starting sequence from the most probable sequence of steps given the observations. Doing the same thing
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Hence, we can eliminate the \([\text{Cloudy, Sunny}]\) starting sequence from the most probable sequence of steps given the observations. Doing the same thing
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